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11x^2+91x+130=0
a = 11; b = 91; c = +130;
Δ = b2-4ac
Δ = 912-4·11·130
Δ = 2561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(91)-\sqrt{2561}}{2*11}=\frac{-91-\sqrt{2561}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(91)+\sqrt{2561}}{2*11}=\frac{-91+\sqrt{2561}}{22} $
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